题解
模拟即可
不需要RMQ也不需要记忆化…因为数据好像超出了100001
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using namespace std;
typedef long long ll;
int read(){
int f = 1, x = 0;
char c = getchar();
while(c < '0' || c > '9'){if(c == '-') f = -f; c = getchar(); }
while(c >= '0' && c <= '9')x = x * 10 + c - '0', c = getchar();
return f * x;
}
int rec(int cur){
if(cur == 1)return 1;
if(cur & 1)
return rec(3 * cur + 1) + 1;
else
return rec(cur >> 1) + 1;
}
void init(){
}
void solve(){
int l, r;
while(scanf("%d%d", &l, &r) == 2){
int aans = 0;
if(l < r){
for(int i = l; i <= r; ++i)
aans = max(aans, rec(i));
}else {
for(int i = r; i <= l; ++i)
aans = max(aans, rec(i));
}
printf("%d %d %d\n", l, r, aans);
}
}
int main(){
init();
solve();
return 0;
}