题解
水DP。
按照时间变化递推即可。1
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using namespace std;
typedef long long ll;
int read(){
int f=1,x=0;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=-f;c=getchar();}
while(c>='0'&&c<='9')x=x*10+c-'0',c=getchar();
return f*x;
}
int n,m,pos1[1005][2],pos2[1005][2],f[1005][1005];
char s1[1005],s2[1005];
void movement(char c,int &x,int &y){
if(c=='N')y++;if(c=='S')y--;
if(c=='E')x++;if(c=='W')x--;
}
int sqr(int a,int b){
return (pos1[a][0]-pos2[b][0])*(pos1[a][0]-pos2[b][0])+
(pos1[a][1]-pos2[b][1])*(pos1[a][1]-pos2[b][1]);
}
void init(){
n=read(),m=read();
pos1[0][0]=read(),pos1[0][1]=read();
pos2[0][0]=read(),pos2[0][1]=read();
scanf("%s%s",s1+1,s2+1);
for(int i=1,x=pos1[0][0],y=pos1[0][1];i<=n;i++)
movement(s1[i],x,y),
pos1[i][0]=x,pos1[i][1]=y;
for(int i=1,x=pos2[0][0],y=pos2[0][1];i<=m;i++)
movement(s2[i],x,y),
pos2[i][0]=x,pos2[i][1]=y;
}
void solve(){
memset(f,0x14,sizeof(f));
f[0][0]=0;
for(int i=1;i<=n;i++)
f[i][0]=f[i-1][0]+sqr(i,0);
for(int i=1;i<=m;i++)
f[0][i]=f[0][i-1]+sqr(0,i);
for(int i=1;i<=n;i++)
for(int j=1;j<=m;j++)
f[i][j]=min(f[i-1][j],f[i][j-1]),
f[i][j]=min(f[i][j],f[i-1][j-1]),
f[i][j]+=sqr(i,j);
printf("%d\n",f[n][m]);
}
int main(){
init();
solve();
return 0;
}